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3.9=18x+4.9x^2
We move all terms to the left:
3.9-(18x+4.9x^2)=0
We get rid of parentheses
-4.9x^2-18x+3.9=0
a = -4.9; b = -18; c = +3.9;
Δ = b2-4ac
Δ = -182-4·(-4.9)·3.9
Δ = 400.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-\sqrt{400.44}}{2*-4.9}=\frac{18-\sqrt{400.44}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+\sqrt{400.44}}{2*-4.9}=\frac{18+\sqrt{400.44}}{-9.8} $
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